
Quantitative Aptitude is a vital component of various competitive exams, including the Common Law Admission Test (CLAT). Among the topics tested, the concept of “averages” holds significant importance. Averages, often referred to as mean, are fundamental in understanding data distribution, making predictions and drawing conclusions. In this article, we will delve into the concept of averages, explore examples and discuss strategies to solve average-related problems in the quantitative aptitude section of CLAT.
An average or mean, is a measure that represents the central value of a set of data. It is calculated by summing up all the values in the dataset and dividing the sum by the total number of values. The average is used to represent a typical value in a dataset, helping to analyse the overall trend.
Let’s explore a few examples to better understand the concept of averages:
Example 1: Suppose we have the following test scores of a student in five subjects: 85, 78, 92, 70 and 88. To find the average score, we add up all the scores and divide by the total number of scores:
Average=85+78+92+70+885=4135=82.6Average=585+78+92+70+88=5413=82.6
So, the average test score is 82.6.
Example 2: Consider a scenario where a team of cricket players scored the following runs in five consecutive matches: 45, 60, 75, 80 and 95. The average runs can be calculated as:
Average=45+60+75+80+955=3555=71Average=545+60+75+80+95=5355=71
Hence, the average runs scored by the team are 71.
When facing average-related problems in the CLAT quantitative aptitude section, it’s essential to approach them methodically. Here are some strategies to tackle such problems effectively:
Let’s work through a couple of example problems to solidify the strategies discussed:
Problem 1: The ages of a group of friends are 25, 28, 30, 22 and 27 years. Calculate the average age of the group.
Solution: Sum of ages = 25+28+30+22+27=13225+28+30+22+27=132 Total count = 5
Average = 1325=26.45132=26.4
So, the average age of the group is 26.4 years.
Problem 2: The scores of a student in three subjects are as follows: Mathematics – 90, English – 85 and Science – 92. If the weights of these subjects are 4, 3 and 5 respectively, calculate the weighted average score.
Solution: Weighted sum = 4×90+3×85+5×92=360+255+460=10754×90+3×85+5×92=360+255+460=1075 Total weight = 4+3+5=124+3+5=12
Weighted average = 107512=89.58121075=89.58
The weighted average score is approximately 89.58.